How to Zip files in JAVA : Complete Code Tested OK

String multiplezips = "c:\\tobo\\textfile1.txt,c:\\tobo\\textfile2.txt";
String zipFile = "c:\\tobo\\file_1.zip";
String[] srcFiles = multiplezips.split(",");
      try {
          // create byte buffer
          byte[] buffer = new byte[4096];
          FileOutputStream fos = new FileOutputStream(zipFile);
          ZipOutputStream zos = new ZipOutputStream(fos);
          for (int i=0; i < srcFiles.length; i++) {
              File srcFile = new File(srcFiles[i]);
              FileInputStream fis = new FileInputStream(srcFile);
              // begin writing a new ZIP entry, positions the stream to the start of the entry data
              zos.putNextEntry(new ZipEntry(srcFile.getName()));
              int length;
              while ((length = fis.read(buffer)) > 0) {
                  zos.write(buffer, 0, length);
              }
              zos.closeEntry();
              // close the InputStream
              fis.close();
          }
          // close the ZipOutputStream
          zos.close();
      }
      catch (Exception ioe) {
          System.out.println("Error creating zip file: " + ioe);
      }

Above code illustrates conversion of few files into a zipped file.

Variables

multiplezips – This variable contains the files to be zipped in a comma seperated string.

zipFile – This is a string containing the name of the final file to be formed after compressiong all the child files from the variable multiplezips.

The above code is tested and working. Copy, paste and run.

🙂

For any queries do post in comments please.